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 Question roller coaster: kinetic energy ( Physics Help and Math Help - Physics Forums Introductory Physics )Updated: 2008-05-04 03:33:40 (15)
 roller coaster: kinetic energy A roller coaster car may be approximated by a block of mass m. The car, which starts from rest, is released at a height h above the ground and slides along a frictionless track. The car encounters a loop of radius R, as shown. Assume that the initial height h is great enough so that the car never loses contact with the track. http://session.masteringphysics.com/...3/MPE_ug_2.jpg so, i know kinetic energy = .5m(v^2) and centripetal force in circle is m(v^2)/R so that if i play around with the equations i can get KE = 0.5m(gR) ... but how do i take into account the height if i have to give my answer in terms of m, g, h, and R? Anyone out there who can solve this thing?
 Answers: roller coaster: kinetic energy ( Physics Help and Math Help - Physics Forums Introductory Physics )
 roller coaster: kinetic energy Find an expression for the kinetic energy of the car at the top of the loop. Express the kinetic energy in terms of m, g, h, and R. forgot to add that what's above is the problem! jaded18
 roller coaster: kinetic energy Just use conservation of energy... I don't think you need to deal with centripetal motion or anything. learningphysics
 roller coaster: kinetic energy i can't work just on that. what do you mean by 'just use conservation of energy'. i need to express my answer in terms of those variables i listed above. jaded18
roller coaster: kinetic energy

 Originally Posted by jaded18 i can't work just on that. what do you mean by 'just use conservation of energy'. i need to express my answer in terms of those variables i listed above.
What is the energy of the coaster at the beginning when it's at rest? Take the gravitational potential energy on the ground to be 0.

learningphysics

 roller coaster: kinetic energy The energy of the coaster at the beginning is potential energy which is just mgh. jaded18
roller coaster: kinetic energy

 Originally Posted by jaded18 The energy of the coaster at the beginning is potential energy which is just mgh.
Yes, now at the top of the loop, it has potential energy mg(2R), and kinetic energy. can you use conservation of energy to solve for kinetic energy?

learningphysics

 roller coaster: kinetic energy thanks! i got it ... now what if i want to find the minimum initial height h at which the car can be released that still allows the car to stay in contact with the track at the top of the loop? how would i approach this one? jaded18
roller coaster: kinetic energy

 Originally Posted by jaded18 thanks! i got it ... now what if i want to find the minimum initial height h at which the car can be released that still allows the car to stay in contact with the track at the top of the loop? how would i approach this one?
Now you'd use the centripetal acceleration... what does the velocity need to be at the top of the loop for the car to maintain contact?

learningphysics

 roller coaster: kinetic energy well acceleration is V^2/R . and so min velocity would be v = gR ... jaded18
 roller coaster: kinetic energy sorry, v = (gr)^(1/2) jaded18
roller coaster: kinetic energy

 Originally Posted by jaded18 sorry, v = (gr)^(1/2)
yup. so what is the total energy of the coaster when it is at the top of the loop? It has that same energy when it is released from rest.

learningphysics

 roller coaster: kinetic energy mgh... sorry i'm not getting it jaded18
 roller coaster: kinetic energy i set mgh-mg2R = 0.5(mv^2) and plugged in what i got for v ... so i ended up with h=3R but i think i'm off by some multiplicative factor ??? the ans should be in terms of R by the way... jaded18
roller coaster: kinetic energy

 Originally Posted by jaded18 i set mgh-mg2R = 0.5(mv^2) and plugged in what i got for v ... so i ended up with h=3R but i think i'm off by some multiplicative factor ??? the ans should be in terms of R by the way...
can you show how you get h = 3R, I'm getting h = 2.5R

learningphysics

roller coaster: kinetic energy

 Originally Posted by jaded18 ah, stupid calc. error. thanks lots learningphysics. you made my day haha
no prob.

learningphysics

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