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 Question Prove Inequality using Mean Value Theorem ( Physics Help and Math Help - Physics Forums Calculus Beyond )Updated: 2008-11-25 05:55:13 (3)
 Prove Inequality using Mean Value Theorem 1. The problem statement, all variables and given/known data Essentially, the question asks to use the mean value theorem(mvt) to prove the inequality: abs(sina - sinb) abs(a - b) for all a and b 3. The attempt at a solution I do not have a graphing calculator nor can I use one for this problem, so I need to prove that the inequality basically by proof. What I did was to look at the mvt hypotheses: if the function is continous and differetiable on closed and open on interval a,b, respectively. However, the problem I am having is that I am getting thrown off by the absolute values and the fact that I've never used mvt on inequalities. I know the absolute value of the sin will look like a sequence of upside-down cups with vertical tangents between them. Hints most appreciated.
 Answers: Prove Inequality using Mean Value Theorem ( Physics Help and Math Help - Physics Forums Calculus Beyond )
 Prove Inequality using Mean Value Theorem Assume a>b, then sina-sinb=(a-b)cosc, for some b
 Prove Inequality using Mean Value Theorem Wait, are you considering that abs(...) = absolute value of the sum? Khayyam89
 Prove Inequality using Mean Value Theorem The mean value theorem tells you (sin(a)-sin(b))/(a-b)=sin'(c)=cos(c) for some c between a and b, as boombaby said. Take the absolute value of both sides and use that |cos(c)|<=1. Dick
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