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Question Solving fourth order differential equation URGENT ( Physics Forums Differential Equations )
Updated: 2010-07-26 04:20:08 (10)
Solving fourth order differential equation URGENT

I have two second order differential equation which needs to be solved.

x1''(t) = 8 x2(t)
x2''(t) = 2 x1(t)

I have the initial conditions, x1(0) = 0, x2(0) = 1, and terminal conditions x1(pi/4) = 1, x2(pi/4) = 0.

Can anyone help me solve these equations?? What I did was to write the equations in terms of x1 and x2 respectively, but that gives me a fourth order differential

x1''''(t) = 16 x1(t)
x2''''(t) = 16 x2(t)

and I do not know how to solve for these. Can any one help please??

Answers: Solving fourth order differential equation URGENT ( Physics Forums Differential Equations )
Solving fourth order differential equation URGENT

You know that the exponential, sine and cosine return to their original form after differentiating them four times. So try a solution of the form LaTeX Code: c_1 e^{a t}+c_2 e^{-at}+c_3 \\sin(at)+c_4 \\cos(at) .

Cyosis

Solving fourth order differential equation URGENT

So the solution would be
x1(t) = c1 e^(16t) + c2 e^-(16t) + c3 sin(16t) + c4 cos(16t)??

sasikanth

Solving fourth order differential equation URGENT

No you found the wrong a. Differentiating e^16t 4 times would give 16^4 e^16t, which is not a solution.

Cyosis

Solving fourth order differential equation URGENT

would a = 4 be the correct solution??

sasikanth

Solving fourth order differential equation URGENT

I am not sure why you have to ask. Take the derivative of your function with a=4 , four times and you will see that it is not the correct solution.

Cyosis

Solving fourth order differential equation URGENT

I am sorry, I was taking the second dervivative for some reason. I conclude that a = 2 would be thr right solution. Am I correct??

sasikanth

Solving fourth order differential equation URGENT

Yes that's correct.

Cyosis

Solving fourth order differential equation URGENT

In order to solve for c1,c2,c3 and c4, I would need the second differential of x1. Would that be x1'' = c1 e^4t +c2 e^-4t ??

sasikanth

Solving fourth order differential equation URGENT

Originally Posted by sasikanth
I have two second order differential equation which needs to be solved.

x1''(t) = 8 x2(t)
x2''(t) = 2 x1(t)
Your equations are linear with constant coefficients. I would handle either the following ways

1. Apply the Laplace transform to the equations - this will transform the problem to solving algebraic system of equations or

2. Let the solution be x1(t)=q1ert and x2(t)=q2ert . Substitute this assumption and you can determine r, q1 and q2 from eigenvalue-eigenvector equation.

matematikawan

Solving fourth order differential equation URGENT

I got the solution to the equation using the fourth order differntial, but am stuck wolving for the constants c1,c2,c3,c4. If I wanted the second order differntail for x1, would that be x1'' = c1 e^4t +c2 e^-4t ??

sasikanth

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